244 On the Computation of the Moon's Motion in Right Ascension* 



observed at Greenwich at 13 h 36 m apparent time, and at the 

 Cape of Good Hope at 12' 1 20 ra apparent Greenwich time; 

 each being estimated to the nearest minute. Consequently 

 the middle point of time, between the two observations, is 

 \ (c + x) = O h 58 m from the preceding midnight : and the 

 successive differences of the moon's right ascension, taken from 

 the Nautical Almanac, will be as follow : viz. 



oii* ^ c d e 



Feb. 8. at M = 154 31 52 o , n 



+ 5 54 21 / // 

 9. at N = 160 26 13 5 8 " 



-f 5 49 13 -f 51 // 



at M = 166 15 26 4- 17 -f 7 



+ 5 44 56 +58 -4, 



10. at N = 172 22 -3 19 -f 3 



+ 5 41 37 +61 



atM = 177 41 59 -2 18 



+ 5 39 19 



11. atN = 183 21 18 



Therefore, by entering the table with the argument \ (c + x), 

 we have the respective logarithms of the several quantities as 

 under : viz. 



=-2-35793 c = + l-76343 d =+0-69897 e =0-60206 

 B=-9-62264 C = + 8-66519 D =+8-87550 E =-7-70026 



Bb = + 1-98057 Cc= 



and, taking the natural numbers of these logarithms, we shall 

 find the value of M to be as follows : viz. 



a = 5 44 56-000 

 Eb = + 1 35-625 

 C c = + 2-683 

 Dd = + 0-375 

 Ee = + 0-020 



M = 5 46 34-703 (log = 4-3179526) 

 which is the moon's motion in right ascension for the twelve 

 hours, of which J (c + x) is the middle point of time. So that 

 if we had s = 24 h 3 m 57 $ '6, and A = + 2 m 26 S< 315, the 

 operation would be as follows : viz. 



7 is = 5-8127677 

 M = 4-3179526 



1-4948151 

 A = O h 2 m 26 S> 315 = 2-1652889 



A = 1 16 11-976 = 3-6601040 



x = 1 13 45-661 



In 



