:-m'>ts\'l^ K\ at do0^ Temperatures* - mO«^Vj^ 147 



the specific gravity df-vv^ei-,^ the result bf this being 9'796; 

 What then is the speelfic gi-mity of the dicohol — if not 8141? 



^ It is fbun(l|Vtl^i?:ru)e,;~ 



Divide 1000, the quantity weighed, by the loss of weight, 

 and by the quotient divide the density of silver, according 

 to its visible qontll^elion ; the quotient will be the specific 

 gravity of the alcohol, or fluid in which it is weighed. 



».Xhus,at the temperature 56' below zero, ihc loss of weight 

 i#3i^*;l ) by whic));,t itrrJiOOO (the quantity weighed) be di- 

 vided, tl\e quotient is l^-OSS, by which 10-4268 (ihe density 

 ^f silver, according to its visible contraction) is divided ; and 

 tl?^t^otient is '8665, the specific gravity of the alcohol at 

 56^ below zero. Thus, -0524 is the sum of variation of the 

 speciiic gravity of alcohol in 106% or 00049434 is the varia- 

 tip4j in each degree of temperature : from it the specific 

 grfiyities at these N^everal temperatures are calculated. 



At 135^ the specific gravity of alcohol is -77208 



>iJ} i: 117 -78098 



j^EBp 100 — 4l-^c^ -78938 



' 50 •' : ■ '" -81410 



zero — -83882 



50 below zero -66353 



52 ■ -86482 



56 -86650 



K. Then taking the specific gravity of the alcohol at anv 

 certain temperature, and the loss expressed at C ; What will 

 be the specific gravity of the silver according to C ? 



It is found by this rule : — 



Divide 1000 (the quantity weighed) by the loss of weight, 

 and multiply the qudtient by the specific gravity of the al- 

 cohol or fluid in which it is weighed. 



Thus, at 5Q^ below zero the loss of weight is 63-1, ac- 

 cording to C ; by which if 1000 be divided, the quotient is 

 12*0337 ; which, multiplied by "8665, the density of alco- 

 hol, as at I, in that temperature the product is 10-427, the 

 specific gravity of silver at 5Q' below zero. 



Then, having ascertained the specific gravity of silver and 



K2 of 



