of Notation in Chemistry. 443 



The soda appears to be the smallest of the ingredients. If we 

 multiply all the numbers by 2.37, the soda will become 32, or 

 one atom ; and, as the proportions will not be altered, we 

 shall have the corresponding numbers of atoms of the other 

 constituents, by dividing by the weight of one atom of each. 

 We have thus, 



Silica 4 , 130.82 number of atoms r= 8.19 

 Alumina . 54.49 . . . . ] 3.02 



Soda . . 32.09 .... 1 



Water . . 19.62 .... 2.18 



Since the numbers of atoms must be whole numbers, 8, 3, 1, 2 

 are the true results, and the formula is8S-f3A + N + 2q. 

 These elements may be variously grouped. The most pro- 

 bable arrangement appears to be 3(2 S + A) + 2S + N + 2q t 

 as the atomic constitution of the analcime analyzed in this 

 case. 



I taker as another example, two analyses of Apophyllite ; 

 one by Vauquelin, and the other by Berzelius : 



V. B. One atom. 



Silica . . 51 52.13 .. (16) 



Lime . . 28 24.71 .. (28) 



Potassa(K) 4 5.27 .. (48) 



Water . . 17 16.20 .. (9) 



Fluoric Acid .82 . . (20) 



100 99,13 



The fluoric acid is probably accidental. If wesuppose thepotassa 

 to be essential, we must multiply the parts of first analysis by 



48 

 12, and those of the second by r^jy, r 9.1 1, and then divide 



by the weights of one atom. We have thus, 



V. Atoms. B. Atoms. 



S 612 38 474.90 29.68 (30) 



C 330 18 225.11 8.04 (8) 



K 48 1 48 1 (1) 



q 204 22 or 23 147.58 16.39 (16) 

 The second analysis would give 30 S + 8 C + K + 16 7, 

 which might be grouped thus : 8(3 S + C) + 6 S + K + 16 q ; 

 and this is given by Berzelius as the constitution of apophyllite. 

 But Yauquelin's gives us 38S + 12 C -h K + 22 q, which 



