Dr. Blyth on the Composition ofNarcotine. 367 



I. ir. 



Carbon 43*72 43'56 



Hydrogen .... 4'17 4*30 



From which the following formula is deduced : — 



Calculated. Found. 



C46 = 3450 43-70 



U^- 325 4-10 



N = 177 

 0,4 = 1400 



Pt = 1233-5 15-81 15-80 



CI3 = 1327-9 



7913-4 atomic weight of double salt. 

 2573-9 = HCl + PtClg. 



5339-5 = calculated atomic weight of narcotine. 

 Formula of narcotine taken from the above: 



C46 H,, N 0,4. 

 The same formula is deduced from the analyses of M. 

 Liebig, Regnault, &c. 



The atomic weight of carbon employed in this memoir 

 being 75, gives in 100 parts for the analyses of these che- 

 mists — 



Liebig. Regnault. A. W. Hofmann. 



> ^ , 



Carbon . 64-09 64*01 64-50 64*53* 



Hydrogen 5-50 5'9Q 5-97 6-21 



Nitrogen . 2-51 3*46 3'52 3-30 



Oxygen . 27-9 26-57 26-01 25-96 



100-00 100-00 100 00 100-00 



Formula calculated from these numbers — 



C46 H,, N 0.4. 



Calculated. 

 C46 =3450 64*61 



H25= 312-5 5-85 



N = 177 3-31 



0,4 = 1400 26-23 



5339-5 100*00 



B. Products of Decomposition. 

 I endeavoured by following out the products of decomposi- 

 tion produced by bichloride of platinum to see how far the 

 analyses of these bodies would support the formula given 

 above for narcotine. 



* By this analysis the following numbers were found : — 



04649 grm. narcotine gave COo =: 1*100, water =r 0"26. 

 0548 grin. do. gave 289 platinchloride ammonium. 

 0-4697 grm. do. gave 0-219 ditto. 



