K-PAETITIONS OF N. 141 



which gives for F 



Next, to find Q^x)', we have 

 (flP,y=x-Fa;4-(AV+B'a;H-C')*2,_,+G, 



the first being equal to the difference of the other two. As 

 this difference has no terms at all when x is even, we must 

 have 



whatever be x, which requires that all the co-efficients in Fa: 

 should be zeros. When x is odd, 



*^^~ 2880, -2880 >^ 12, 



and -36A'+6B= J^, or B'=. ^^ 



'2880, 2880, 



whence 



Now (fPx-e)' has no terms at all, iixz 6 ; whence, 

 if ir=6e+c, cZ7, 



[.P^,]'=(.P.)', or 



+C-»2,_,. 

 Therefore G=0, and 



2880C'=|?c3— 60C+90, 



