MENAI BRIDGE: '401 



weight the chain will bear; the strain being 

 greatest on the top link, we have, force in AC^ 

 or in AE = 7020 tons, angle DAE = 16'. lO', 

 angle BAG = 18". 3'. 



Resolving the tension in AE and AC into its 

 vertical and horizontal effects gives as below : — 



7020 xnat. sin. 16°. 10' = 7020 x .27843= 1954f 

 tons = force in DE = weight of bridge borne 

 by one pier (1), 



7020 X nat. sin. 18^ 3'= 7020 x .30985 = 2175 

 tons = force in B C = vertical pressure from 

 side chain - (2), 



7020xnat. cos. 16^ 10'= 7020 x .96045 = 6742 

 tons = force in AD = horiz. tension from 

 catenary (3), 



7020 x nat. cos. 18*. 3' = 7020 x .95078 = 6674 

 tons = force in A B = horiz. draw from 

 side chain - (4). 



Doubling the number obtained in equation (1), 

 we have 2 x 1954i = 3909 tons for the whole 

 weight, the bridge would bear distributed over 

 its road-way. 



From equations (1) and (2) we have 1954 

 3 E 



