on Alcohol at common Temperatures, 366 



100 parts of water at 8° C. dissolved 0'56 of the prisms and 

 0*50 of the needles. Both solutions gave the same reactions 

 with general reagents. 0*558 grm. of the prisms, boiled with 

 a clear solution of caustic lime for a short time, then acidu- 

 lated with acetic acid, and the oxalate of lime filtered off and 

 converted by the usual method into carbonate of lime, yielded 

 0254 of the latter substance. This corresponds to 0"325 of 

 oxalate of lime. 



0-391 grm. of the needles, treated in a similar manner, gave 

 0-176 Ca^ CO^ or 0-225 oxalate of lime. Therefore from 100 

 parts — 



{prisms 58-2 oxalate of lime 

 needles 57*5 



If the decomposition takes place according to the equation-— 



2(C2 W Ca 0-*) + Ca HO = C^ Ca^ 0^ + (C^ H^ Ca 0^) + 2W0, 



y ,_• ^ -^- ' 



Oxalate of hme. Glycolate of lime. 



then 57*6 per cent, of oxalate of lime should have been found. 

 These experiments show that both kinds of crystals belong to 

 the same substance, and, moreover, they confirm the formula 

 C2 H3 Ca 04 for glyoxylate of hme. 



The preparation of a double salt of glyoxylate and glycolate of 

 lime was described in the beginning of this paper. It forms a 

 white crystalline powder, more easily soluble in hot than in cold 

 water. The warm saturated solution solidifies on cooling, form- 

 ing a mass like gelatine, which after a few days' standing becomes 

 crystalline. 



Nitrate of silver, chloride of copper, acetate of lead, and lime- 

 water, give the same reactions with this substance as with glyoxy- 

 late of lime. By repeatedly dissolving the compound in hot 

 water and recrystallizing it, it appears to be decomposed into 

 C^H^CaO^andC^H^CaO^ 



Analysis gave the following results : — 



0-246 grm., dried at 120° C, gave O'llO grm. Ca^O CO^. 



0-148 grm., dried at 120° C, yielded 0-048 grm. water and 

 0-119 grm. CO^. In 100 parts,— 



Carbon . . . 21 '92 

 Hydrogen . . 3-60 

 Calcium . . . 18-00 



The formula 2{C^ W Ca 0^) + C^ H^ Ca 0^ + H HO requires-- 



Carbon ... 21*49 

 Hydrogen . . 3*28 

 Calcium . . . 17-91 

 Oxygen 



