98 Tables of the Stm's Mean Right Ascension. 



h m s 



Year, 1825, Table I. ... 3 24.502 Table I. Q, 251 



Month, Jan. 10. Table II. ... 19 15 25.553 II. 1 



Day, 7 II. ... 27 35.887 II. 1 



S3, Lunar Nutation III. ... 1.058 Sum, 253 



0, Solar Nutation IV. ... 0.0C2 = 297°.5 



D, Lunar Equation IV. ... 0.005 ^ = 281 .6 



r = 19 46 27.067 



s = 2 18 49.860 



,_-r = . , 6 32 22.793 



By my Mathematical Tables, XXXI. 



h m s m 



6 give 58.977 



32 ... 5.242 



23 ... 0063 



jf_r = 6 32 23 give a=l 4.282 — 1 4.282 



»n = mean solar time, 6 31 18.511 



Example 2 Suppose the observation had been made at &* 31" 18».511 



mean solar time, and the corresponding sidereal time were required, the ope- 

 ration would have been performed as follows : 



h m s 



m= 6 31 18.511 



r = . • 19 46 27.067 



h m s 



By Mathematical Tables XXX. 6 0/- 69.139 



31 -| 5.092 



18.5 I 0.051 



s = sidereal time, . . . 2 18 49.860 



Since the tables of the sun's mean right ascension are adapted to the meri- 

 dian of Greenwich, a correction must be applied when the computations are 

 made for any other meridian. This correction may be conveniently taken 

 from Table XXX. of my Tables. 



Example 3 Required the correction necessary to adapt these tables to the 



meridian of Paramatta, in longitude 10** 4™ 5s E. 



li m 8 m 8 



By Table XXX . . 10 give 1 38.565 



4 ... 0.658 



5 ... 0.014 



Total correction for . . 10 4 5 = — 1 39.237 



which is negative or — because the longitude is east. 



Ex. 4. — Required the correction for Edinburgh, in longitude 12" 42 .5 W. 



m 8 

 By Table XXX 12 gives 1.972 



42.5 ... 0.118 



Total correction for .... 12 42.5 = + 2.090 



which is additive, because the longitude is west. 



