398 British Association for the Advance?nent of Science. 



residue of sulphate of potash. The mean of three analyses gave 



for its composition, 



Potash 29*51 



Sulphuric acid 50*10 



Methylic aether 14*39 



Water of crystallization 6*00 



100-00 

 which agrees with the formula : 



• 2 S+K+(2C + 8H+0) + H' 



The sulpho-methylate of baryta crystallizes in plates. The mean 

 of two analyses gave 



Baryta 38*50 



Sulphuric acid 40*21 



Methylic aether 11*49 



Water of crystallization 9*80 



100-00 

 This salt was analysed by Dumas. His result : 



Baryta 38*6 



Sulphuric acid 40*4 



Methylic aether 11*1 



Water of crystallization 9*9 



100-0 

 Both analyses indicate the same formula : 



2S + Bb+(2C + 3H+0) + 2H 

 The sulpho-methylate of lime crystallizes in octohedrons, which 

 are anhydrous. They deliquesce, and by the mean of two analyses 

 are composed of, 



Lime 21*41 



Sulphuric acid 60*25 



Methylic aether 18*34 



100*00 



giving the formula 2 S + Ca + (2 C + 3 H + O). 



The sulpho-methylate of lead usually obtained is in long prisms, 

 which readily deliquesce, and are very easily decomposed, being re- 

 solved into sulphate of methylene and sulphate of lead. The mean 

 of seven analyses of this salt gives for its composition, 



Oxide of lead 49*76 



Sulphuric acid 35-93 



Methylic aether 9*81 



Water of crystallization ...... 4*50 



100-00 

 giving the formula 2 S + P6 + (2 C + 3 H + O) + H. 



