Dr. Schunck on Ruhian and its Products of Decomposition, 507 



II. 0*4885 grm. of another preparation gave 0*6865 carbonic 

 acid and 0*2060 water. 



0*1540 grm. gave on being incinerated 0*0370 carbonate of 

 lime, containing 0*02076 lime = 13*48 per cent. After being 

 treated with sulphuric acid and again heated, it weighed 

 0*0500 grm., which, estimated as sulphate of lime, is equivalent 

 to 0*02062 lime= 13-39 per cent. 



From these numbers may be deduced the formula C^H^N^O'*^ 

 -f 4CaO, as the following calculation shows : — 



^^^•'^Carbon . 

 Hydrogen 

 Nitrogen 

 Oxygen . 

 Lime 



830 100*00 100-00 



If this be the true composition of erythrozym, it stands in a 

 very interesting relation to that of rubian. If to 1 equiv. of 

 rubian be added the elements of 2 equivs. of nitric acid, the 

 sum will represent the composition of the organic substance 

 contained in the erythrozym in combination with lime, C^H^ 0^® 

 + 2NO^=:C^H34N2 04o. 



I shall now give the results of an analysis of erythrozym which 

 had been employed for the decomposition of a quantity of rubian, 

 and then treated successively with cold water and boiling alcohol 

 until all the products of decomposition were entirely removed. 



0*5330 grm., dried at 100° C. and burnt with oxide of copper 

 and chlorate of potash, gave 0*8325 carbonic acid and 0*2220 

 water. 



0*2780 grm. gave 0*1835 chloride of platinum and ammonium. 



0*0645 grm. gave on being incinerated 0*0130 carbonate of 

 lime, containing 0*00729 lime. 



These numbers lead to the following composition : — 



696 100*00 100*00 



If this composition be compared with that of the substance in 

 its undecomposed state, the exact nature of the change which it 

 undergoes during the process of fermentation will be apparent. 

 It appears that the change consisted in this case in the loss of 



2L2 



