IJK) Mr Galbraith's Barometric Mecumrement of 



following operation will give the height, from observations made 

 at Ben-Lomond. 



INCHES. 



B =30.328, T = 75'.5, / *= 75°.5, </ =00^.0, /=-5354 



I. E = —.033 



B' =30.295 



b =27.064\ T^ = 60.1 <'=_6a2 d = 49.5, f'= -3284 



Cor. =+.034/' r — t'=15.4' / + /'= 135.7' /+/' = 0.8638 



B' + 6' = 67.393 



B'— A'= 3.197 log. bar. co-efficient or C .... 4.780032 



t-\-f = 135.°7 log. E' 0.027540 



Lat. = 56° log. . . . . . . . . 9.999566 



B'—i'o/= 30.241 log. 1.480596 



i'—j'^/' = 27-065 log. 1.432408 



DifF. 0.048188 log. . . * . . . 8.682946 

 E" =1.0153 log. 0.006594 



H' =3138.2 log. 3.496678 



h = 2.0 = height of cistern of lower bar. above the lake, 



h' = 2.0 = height of summit above the cistern of upper barometer. 



h'-' =■ 32.0 = height of surface of lake above the sea, 



T. H = 3174.2 = height of Ben-Lomond above the mean rise of half tide at 

 Dunbarton, by observations taken with barometers at the top and bottom. 



We now proceed to calculate the height, by comparing observations made 

 at the Caltonhill with those on the top of Ben -Lomond, distant about sixty 

 miles from each other. 



INCHES. 



B =29.942, T=75°.4 < = 7r.8, rf=58.°0, /= .4928 



I. E = +.021 



B' =29.963 * 



b =27-064 "I t' = 60.1 r= 60.2 rf' = 49.5, f'= .3284 



Cor. =+-034/' t — t'= 15.3' < + /'=132.0' /+/' = 0.8212 



6" =27-098 E''=1.M46 

 B' + 6'=57061 



B— 6' = 2.865 log C . . 4.779966 



t-\-e =132.°0 logE' 0.026124 



Lat. = 56° log 9.999566 



B'— yV/ = 29.9 14 log. 1.475875 



fi/—-!^/'- 27.065 log- 1-432408 



Diff: 0.043467 log. 8.638160 



E'r , = 1.0146 log. ... .... 0.006295 



H' = 2819 log = height of Ben-Lomond above the Caltonhill. 3.4501 1 1 



h = 355 = height of Caltonhill bar. above the sea, 



h' = 2 = height of summit above cistern of barometer. 



T. H = 3176 = height of Ben-Lomond above the sea at Leith. 



