undergone by its Salts at High Temperatures. 309 



(1.) 0-6135 gramme gave 0*4045 sulphate of lime = 27*383 

 per cent, lime ; and consequently the atomic weight, 2600*0. 



(2.) 0*3660 gramme gave sulph. lime 0*241, or 27*344 per 

 cent. iime. 



(3.) 0*335 salt, gave 0*353 sulphate lime, and consequently 

 the atomic weight, 2598*28. 



These give — 



Calculated. Found. 



1. 2. 3. 



1 Malic acid 1461*39 56*71 



2 Lime . . . 712*04 27*14 27*38 27*34 27*40 

 4 Water . . 449*92 17*15 



2623*35 

 The previous analyses of the lime salt dried without heat, 

 shows the necessity of doubling the atomic weight of the acid, 

 as otherwise we should be obliged to give it the formula 



C*H 2 4 CaO + 2£aq.* 

 which is at variance with the atomic theory. 



Acid Malate of Lime. M CaOH 2 + 6 aq. 

 This salt is obtained when neutral malate of lime is dis- 

 solved in nitric acid. It crystallizes in large transparent octa- 

 hedrons. Dried at 100° C. it loses water, and is converted 

 into a viscid, stringy mass. 



0*706 salt gave 0*2345 sulphate of lime, or 13*794 per cent, 

 lime ; atomic weight, 2585*8. 



Calculated. Found. 

 1 atom Malic acid 1461*39 56*10 



1 atom Lime . . . 356*02 13*67 13*79 



7 Water 787*36 30*23 



2604*77 

 Richardson and Merydorf concluded the formula of this 

 salt to be, M Ca O H 2 O + 8 aq. 



Malates of Magnesia. 

 a. Neutral hydrated Malate of Magnesia. 

 M 2MgO + 10 aq 

 M 2 Mg O + 2 aq (100° C). 



This salt is obtained by boiling magnesia in a solution of 

 malic acid, and crystallizing. It loses 8 atoms of water by 

 100° C. 



0*5505 salt gave 0*2708 sulphate of magnesia, equivalent to 

 16*713 per cent, of magnesia; and makes the atomic weight 

 3091*4. 



