254? Dr. E. Schunck on the Substances discovered in 



On calculating the formula C 24 H 16 O i4 for 100 parts, the 

 following results are obtained: — 



24 eqs. Carbon . . 

 16 ... Hydrogen 

 14 ... Oxygen . . 



3399'6 100-00 

 Picro-erythrine contains in 100 parts — 



Stenhouse. 



The formula C 24 H 16 14 therefore expresses the composi- 

 tion of picro-erythrine. The formation of pseudo-orcine still 

 remains to be explained in harmony with the preceding for- 

 mulae. 



If from 1 eq. picro-erythrine . . =C 24 H 16 14 

 we subtract 2 eqs. carbonic acid =C 2 4 



Q22 "16 Ol0 



and add 12 eqs. water . . . . = H 12 



12 



we obtain C 22 H 28 22 



The formula C 22 H 28 22 , calculated for 100 parts, gives — 



22 eqs. Carbon . . 1650 39*29 



28 ... Hydrogen . 349*4 8*32 



22 ... Oxygen . . 2200 52*39 



4199*4 100*00 



On subjecting pseudo-orcine, prepared according to Mr. 

 Stenhouse's method, to analysis, I obtained the following 

 results : — 



I. 0-5695 grm. substance gave 0*8270 carbonic acid and 

 0-4355 water. 



II. 0-4130 grm. gave 0*6020 carbonic acid and 0*3240 

 water. 



It therefore consists in 100 parts of — 



Stenhouse. 



It will be seen that the formulas here adopted for erythric 

 acid, picro-erythrine and pseudo-orcine, agree very well with 



