The Oils of Rosemary and Marjoram, 439 



sulphur, and an organic element. If the mixture of oil of rose- 

 mary and sulphuric acid be distilled, there is obtained a fluid 

 possessing an aromatic, yet alliaceous odour, resembling that 

 of mesitylene. When quite pure this fluid has a specific 

 gravity 0"8678, and boils at about 344° Fahrenheit. It gives, 

 on analysis, the same composition as oil of turpentine ; but 

 I shall defer the details to the memoir on the Chemical 

 Habitudes of the Oils as a Class. To this fluid I have given 

 the name of Rosmarine; but I have not determined its atomic 

 weight, so as to be able to say whether oil of rosemary be a 

 bi-hydrate of rosmarine, and its formula C45 Hgg + 2 HO. 

 I use the word bi-hydrate here, merely in order to re- 

 present the abstraction of 2 HO by the sulphuric acid, and 

 not wishing to involve any consideration of theory, which will 

 be discussed in its proper place in the memoir already al- 

 luded to. 



II. Oil of Marjoram. — {Origanum vulgare.) 



This oil is found in commerce] nearly pure. Its specific 

 gravity is variable ; Mr. Brande found it 0*909 ; while I ob- 

 tained 0*890 1. This arises from the quantity of stearopten 

 which it contains not being constant, though generally large. 

 By rectification several times, so as to deprive it of the solid 

 matter, it is obtained finally of the specific gravity 0*8673, the 

 boiling point being almost completely constant at 322° Fahr. 

 In this state it was analysed. 



A. Material = 0*368 gramme gave 



Water = 0*368 



Carbonic acid = 1*154 



B. Material = 0*2907 gramme gave 



Water = 0*300 



Carbonic acid = 0*905 



C. Material = 0*2854 gramme gave 



Water = 0*295 



Carbonic acid = 0*891 



D. Material = 0*2881 gramme gave 



Water = 0*302 



Carbonic acid = 0*898 

 Hence there is per cent. 



A. B. C. D. 



Carbon = 86*71 86*08 86*33 86*18 



Hydrogen =11*11 11*44 11*44 11*64 



Oxygen = 2*18 2*48 2*23 2*18 



These results are expressible by a very simple formula, 

 C50 H40 0, or 10 {C5 H4} + O, which gives 



