PIERCE. — THE COOPER HEWITT MERCURY INTERRUPTER. 399 



TABLE II. 

 23 Plates in Glass Condenser. 



Coil I and coil II are accurately wound, and their inductances, Li and Lq 

 have been calculated from their geometrical dimensions. 



Zi = 1.06 X 10® magnetic units, 

 Zg = 14.1 X 10® « « . 



Let L = the unknown inductance of the leads, then by Thomson's 

 formula, we have from Table II, 



2 7r V(A + L)C= 2.295 X 10-6 

 2TrVLG' = .585 X 10-5 



2 TT VCA + L)C = 8.03 X 10-5 



(1) 

 (2) 

 (3) 



Eliminating C from (1) and (2), we have L = .073 X 10-®, which, 

 substituted in (2), gives 



C= .1175 X 10-^5 magnetic units, 

 = 1.05 X 105 (jjjj 



Likewise, from equation (3) 



C= 1.04 X 105 



era. 



