370 PROCEEDINGS OF THE AMERICAN ACADEMY 



Normal Equations. 



—5685.7= +38(3+ S94.2i i = +15.53 = +6.83;* 



—32302.0 = +394.2 a + 5807.1 6 a = —310.7 = —136.7 /t 



This value of h reduced to the equivalent for one meter becomes 7.48 /x. 



But from 



T—C.S. & = — 3.29div. 



r— i?i fe = -f-13.80div. 



Whence from 



C.S. — R^. * = +1 7.09 = +7.52 /* 



We have, therefore, for 1 meter, 



h = +^-^"'' + ^-^-'' = +7.50 ^ = +17.04 div. 

 For 1 yard, 



h = +6-8-V + 6.87^ ^ +6.85;x =+15.57 div. 



