RESISTANCE AND CAPACITANCE IN SERIES 



—jX -iXI2 



B^R + ^+R. -^ = R -jX 



Similarly, for the other T {Figure 3.53a), we get for the pi form {Figure 3.53b) 



j^2 2X 



C=-jX-jX+^^ ^ — {X + jR) 



R 



X 



^^ 



X 



D 



I 



(a) 



Figure 3.53 



(b) 



© 



•2|fr*y/?; 



ll(xvR) 



Kn 



"out 



Figure 3.54 



We now notice that B and D are both R — jX, and that if we take out —j 

 as a factor we get B and D both equal to —j{X -\-jR). We now fit the two 

 pi's together again {Figure 3.54) and by inspection 



out 



B in parallel with D 



Fin B in parallel with D -\- Ain parallel with C 



u 



iy + 



1 



^Z R 



4y 



Putting A' 



coC 



R X 

 X~ R 



Fout 



in 



1 + 



1 



coCR — 



1/2 



1 



coCi?/ j 



((?ra/?A 7<9) 



51 



