136 RELATION OF BILE TO FIBRINE. 



elements of the urine of serpents — that is, to neu- 

 tral urate of ammonia, as follows : 



I the formula of choleic acid = C33N H33OH 



Add to this — 



1 eq. uric acid = CioN.H^Ogl^ C N H O 



1 eq. ammonia = N H3 J 



The sum is , = C48N6H40O17 



29. But this last formula expresses the composi- 

 tion of blood, with the addition of 1 eq. oxygen and 

 1 eq. w^ater. 



Formula of blood C48N6H39O15 



1 eq. water = HOI _ „ r\ 



1 eq. oxygen = Oj 



The sum is = C48N6H40O17 



30. If, moreover, we add to the elements of pro- 

 teine those of 3 eq. water, we obtain, with the ex- 

 ception of 1 eq. hydrogen, exactly the same formula. 



Formula of proteine = C48N6H36O14 



Add 3 eq. of water = H3 O3 



The sum is CjgNgHagOi; 



differing only by 1 eq. of hydrogen from the formula 

 above obtained by adding together choleic acid and 

 urate of ammonia. 



31. If, then, we consider choleic acid and urate 

 of ammonia the products of the transformation of 

 muscular fibre, since no other tissue in the body 

 contains proteine (for albumen passes into tissues, 

 without our being able to say, that in the vital jn-o- 

 cess it is directly resolved into choleic acid, and 

 urate of ammonia), there exist in fibrine, with the 



