140 RELATION OF BLOOD TO URINE. 



1 at. uric acid C10N4H4O6 ^ 



4 at. water 1 | /2 at. urea C,^.U,0, 



a . r H4O10 1 1 6 at. carbonic acid Ce O12 

 6 at. oxygenj J ^ _ 



34. The urine of the herbivora contains no uric 

 acid, but ammonia, urea, and hippuric or benzoic 

 acid. By the addition of 9 atoms of oxygen to the 

 empirical formula of their blood multiplied by 5, we 

 obtain the elements of 6 at. of hippuric acid, 9 

 at. of urea, 3 at. of choleic acid, 3 at. of water, and 

 3 at. of ammonia ; or, if we suppose 45 atoms of 

 oxygen to be added to the blood during its meta- 

 morphosis, then we obtain 6 at. of benzoic acid, 

 13^ at. of urea, 3 at. of choleic acid, 15 at. of car- 

 bonic acid, and 12 at. of water. 



5 (C48NeH390i5) + 09= C240N30H195O84 



^6 at. hippuric acid, 6 (CigN Hg O5 ) = CjosNg H^g O30 



9 at. urea 9 (C2 N0H4 O2 ) = Cjg NisHge Oig 



= / 3 at. choleic acid, 3 (CggN H33O11) = ^w^z Hgy O33 



3 at. ammonia ... 3 ( N H3 ) = N3 Hg 



3 at. water 3 ( 1^303)= H3 O3 



The sum is C240N30H195O84 



or — 



5 (C4sNeH3gO,3) + O45 = C24oN3oHig50i20 



6 at. benzoic acid 6 (C14 H5 O3 ) = 0^4 H30 Oig 



27/2 at. urea 27 (C NH. O ) = C27N27H54O27 



= / 3 at. choleic acid 3 (CagNHssOn) = C114N3 H99 O33 

 15 at. carbonic acid, 15 (C 02) = C15 O30 



12 at. water 12 ( . H O ) = H12 O12 



The sum is C240N30H195O120 



35. Lastly, let us follow the metamorphosis of 



