DES iNOMBRES EMIEBS. 249 



2nx3+2 2nx3 

 5»10 =10 x100==(M.I3+IK>I.13-4) 



=M.13-4 



(2nx1)3 / 3\(2n+11 2n+1 



4° 10 =VlO ; =^(M.13-1 =M.13_1 



(2n+i)3+1 (2n+1)3 

 50^0 =10 x10=(M.13-1)(M.13-3) 



=M.13+3 



(2n+-l!3+2 (2n+<)3 

 ^MO ==10 x100^|M.13-l)(M.13-4) 



=M.13+4 



Par suite, on aura : 



N =a + lOai I 10-^02 +10303 +10*a4 -f lO^os + lOeae 

 +10^07 +108a8 +10^09 



2 3 1x3-1-1 1X3+i 



=a+10a +10 a +10 a +10 a +10 a 



12 3 4 5 



2X3 2x3+1 2x3+2 3x3 



+10 a +10 ft +10 a +10 a 



6 7 8 9 



= a -\- (M.13— 1) cri + (M.13— 4) a-i + (M.13— 1)aa 

 +(M.13— 3)a4+(M.13+4ja3+(M.13+1)a6+M.13— SlffT 

 +(M.13— 4)a8 +(MJ3— 1) cg 



=M.13+ ja— 3 ttK —4 02 —as +3 a* +4 cts -\-m — 



—3 a? — 4 as — 09 \ 



=M.1 3+ j a— (3 ai +4 ai +az )+(3 a* + 1 ffs +«« )— 



— (3 07 +4 as +09 )... I 



