DISQUISICIONES TRIGONOMÉTUICAS 



log sen (B = 23°27'14" = 9,59983 



7 

 logsen(c = 4L° 4'16" = 9,81752 



4 

 log cosec (& = 25° 7'35" = 0,371 89 



11 



16' 



log sen C = 9,78946 

 34 



12 



C= 3S°00'4o" 

 180° 



C = 141°59'15" 

 Hallar A. Tomando logaritmos de (b) y (c) se tiene : 

 log cotg X = log cotg b -j- log sec c 

 log sen (A -\- ,v) = log cotg b -\- log tg c -|- log sen x 



log cotg 23°27'14" = 0,30239 



27 

 log sec 41° 4'16" = 0,122GG 



o 



o 



log cotg X = 0,48535 

 65 



30 



X = 18°6'42" 



(6') 



9,76163 



log sen (A + x) = 35°] 6' 



Pig. 28 



A + «'= 35°16'57" 

 180° 



(A + ír?)=rl44°43'03" 



