180 ON THE NEUTRAL SULPHATE OF THE OXIDE OF ETHYLE, 



0.271 BaOS0 3 , which corresponds to 44.248J, BaO 0.544 burned with chromate of lead, 

 gave C O a = 0.0555 ; C = 2.776§ & H O = 0.095 ; H = 1 .930£. 



Experiment. 



44.248 



2.776 

 1.930 



The mother liquid of these crystals contains a salt soluble in alcohol, and which, purified 

 by several crystallizations from spirits of wine, is obtained in fine needles. This salt is a 

 mixture of sulphovinate with isoethionate of barytes. These two salts, when dried over 

 sulphuric acid in vacuo, have exactly the same composition. The substance used for 

 analysis contained a trace of alcohol, which was difficult to get rid of over sulphuric acid. 



Ignited with sulphuric acid, 



No. 1, 0.376 gave BaO S0 3 = 0.219; BaO = 38.271g. 

 No. 2, 0.443 " " =0.258; " = 38.262§. 



No. 1, 0.621 burned with chromate of lead, gave COo = 0.296; C=12.995§ &HO = 

 0.1725; H = 3.075S. 



Calculated. Found. 



38.271 



12.995 



3.075 



The salt analyzed was half sulphovinate, half isoethionate of barytes, as is shown by the 

 following experiment. Sulphovinic acid, as is well known, is resolved at the boiling tem- 

 perature into sulphuric acid and alcohol. Iscethionic acid is unchanged at the same tem- 

 perature. 4.504 grammes of the salt, dissolved in water, and the barytes precipitated by 

 sulphuric acid, gave Ba O S 3 = 2.6005 or Ba O = 37.877£. The filtered solution boiled 

 for several hours, saturated with carbonate of barytes, and the soluble isoethionate of 

 barytes, precipitated by sulphuric acid, gave BaOS0 3 = 1.105, whence BaO=16.776§ 

 of the original salt. But the acids before boiling saturated 37.877£ of barytes, or nearly 

 twice as much. The substance is therefore a mixture half sulphovinate, half isoethionate of 

 barytes. 



As the heavy oil of wine is not one of the products in the action of anhydrous sulphuric 

 acid upon anhydrous ether, the explanation heretofore given of this reaction is necessarily 

 erroneous. In the case of alcohol, the anhydrous acid was said first to form hydratcd bi- 

 sulphatc of the oxide of ethyle, an excess of the acid decomposes the combined oxide of 

 ethyle, depriving it of the elements of water, forming heavy oil of wine, and at the same 

 time setting free the substance C 4 II 4 , which combining with 4S0 3 & HO, form ethionic 

 acid. 



In the case of ether, the sulphuric acid was said to extract the elements of water, form- 



