COFFIN. — EDGE CORRECTIONS IN CONDENSERS. 421 



Let the origin be at t = — 1. Then 



o + o i • 1 



= a log — - + const. .'. const = T = a ir i. 



G ° - 1 



When t — a, z = g + hi ; hence 



g + H= cf§(a + l) i -2«V«+ 1 + a log 1 - :tl - 1 + a*rA 



V V« + i — 1 / 



h = C CtTT, C = — . 



«7T 



From which 



(d) = A(|( a + i)3_2avWl + alog^E — 



a i" \ v a + 1 — 1 . 



The diagram in the ?#-plane consists of two infinite lines with one 

 zero angle, the same as in the preceding problem. 

 The transformation for which is 



dw dt _. 



— = —, or a> = ZMog t. 



v 

 When t is negative, ij/ = v. .*. v = Utt, and w = -log£. 



IT 



The equation for the electricity on the lower face of the square corner 

 from the corner t = — 1 to a point so far in, that the distribution may be 

 considered uniform is 



^ = 4^( 1 ° g ^~ l0g( ~ 1) ) 



We must now find a value of t or of log t for a point at which t is 

 negative and very small. 



Putting t = except in the terms which become large under such 



circumstances : — 



— x + o i — C (§ — 2 a + 2 a log 2 — a log t -f- a it i) 



