WILLIAM D. HARKINS 



143 



the equilibrium box and that at the bottom of each cylinder there is a membrane 

 permeable only to the gas in the cylinder (Fig. 6). 



Force the a mols of the gas A and the b mols of the gas B slowly into the box, and 

 as rapidly as these react take out the e mols of the gas E and the/ mols of the gas F 

 which are formed. 



Since work must be done upon the gases .1 and B to force them into the box, the 

 work they do is negative, or 



Wi = p■^v==-aRt , (11) 



which is obtained from equation (2) by substituting in it the gas law 



p.Av = NRT iN=-a) . 



Fig. 6 



For the gas B 



W,= -hRt. 



Since the gases E and F come out of the box, they do work, and 



Ws=^eRT, 

 Wt=JRT . 



(12) 



(13) 

 (14) 



The gases E and F are now at pressures pE and pp. Let them now be changed to 

 their final state in which the pressures are p^ and pp: 



W^ = RTln-^^, 

 Pe 



(is) 



W%=RTln-^ 



P± 

 P'/ 



(16) 



The total work (W) is the sum of these eight quantities of work, or 



p^ pf p'ep'f 



W^RT In ^-RT In Y^M^+f -^-b) RT . 



^A^B ^A ^E 



(17) 



