FOR HIGH LEVELS IN THE EARTH S ATMOSPHERE. 



55 



Between F= 60 000 and F= 70 000, <^ = 71.5 



Assume further that the mercurial barometer at the level surface, K= 18 550, 

 shows a pressure of 28.496 inches. 



Table 11 for pissso = 28.496 and tr = 67.0 gives pis ,5.50 ~ i^^o ooo = 0.098 inch. There- 

 fore the pressure at the level surface F= 20 000 equals 28.496 - 0.098 = 28 398 inch. 

 For ^j^o 000 = 28.398 and <, = 69.5 Table 10 gives m_»°!!o = 0.666, so that _p3o 000 = 28.398 

 - 0.666 = 27.732 inches. Again when p,om = 27.732 and t, = 73.0 Table 10 gives Uf,Z 

 = 0.645, whence ^^40 000 = 27.732 — 0.645 = 27.087. Proceeding upward in this same 

 manner, the following values of n {^j and p y are obtained : 



TT 30 000 

 ■'■■' 20 000 ■ 



TT 40 000 

 '■•'■ 30 000 



TT .WOOO 

 ^^ 40 000 



TT «0 000 



••' 50 000 ■ 



TT 70 000 

 ^^ 60 000 " 



TT 80 000 

 ■" 70 000 ■ 



n 90 000 

 '■'■ 80 000 ■ 



TT 100000 . 

 ■^^ 90 000 ■ 



TTllOOOO 

 ^^100 000 ■ 



TT 120 000 

 ■'■'110000 ■ 



: 0.666 inch 



= 0.645 " 



= 0.629 " 



= 0.614 " 



: 0.60.3 " 



: 0.590 " 



: 0.577 " 



= 0.565 " 



: 0.555 " 



:0..545 " 



From these values of pressure and the corresponding values of t^ already given, 

 may be obtained graphically the mean value of tr for each pair of the isobaric surfaces 

 p = 28.5 in., 28.0 in., 27.5 in., etc., as follows : 



Between p = 28.5 a 

 " p = 28.0 

 p = 27.5 

 p = 27.0 

 J, = 26.5 

 p = 26.0 

 p == 25.5 

 p = 25.0 



n 

 it 

 l( 

 f( 

 li 

 >t 



d p = 28.0, t^ = 68.0 

 p=27.5, t^ = 7l.O 

 p = 27.0, t^ = 73.0 

 p = 26..5, f^ = 74.0 

 p = 26.0, t^ = 73.5 

 p = 25.5, t^ = 72.0 

 p = 25.0, <^ = 71.0 

 p = 24.5, t^ = 70.0 



