44 



PROCEEDINGS OF THE AMERICAN ACADEMY. 



A = 2 



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2-ir\20i-x>o-*„ 



G" 





G' 



)-313x)0-i 



G 



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D" 



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G 



Au 



ft -2 



BC_A-L 



Z,= (000- 



^ J626-?6" Bp mszof 



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BC 



A, 



G 



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G 



Figure C. Composition of two sections with the same surge-resistance 

 but with different attenuation-constants. 



Equivalent l~l. 



In order to compute hyperbolically the equivalent n of the composite 

 line AD (Figure 6) we proceed as follows: 



Ground either end of the composite line AD, say the end D. Assign 

 the junction-angle 6 2 at BC. Then the angle subtended by the com- 

 posite line at A will be 8 A = 1 + 6 2 hyps. The sending-end resistance 

 of the composite line at A is, by (12) and (37), 



R gA = Zi tanh S A ohms (38) 



= 1,000 tanh 3 = 995.055 ohms. 

 G gA = l/B gA = y x coth S A mhos (39) 



= 0.001 X coth 3 = 10.049,7 X 10 -4 mho. 



