58 



PROCEEDINGS OF THE AMERICAN ACADEMY. 



Rgc = zz tanh S ohms (92) 



= 2,000 tanh 2.158,924 = 1,947.385 ohms. 



Consequently, if o- is the impedance of the load BC in ohms, the 

 sending-end resistance at B is 



RgB = o- + ~2 tanh S G ohms (93) 



= 100 + 1,947.385 = 2,047.385 ohms, 



— ^ii hhH ii i" — >p 



z, = iooo" »; »_■ 1,0*000 j.imfi 



S » 



■ z,o IOOO- ,: ,: i >= iooo' ^.inx>- • 



*, c iooo" 





^ 1^2000" 



A" r 



4J-766-5-" 



0-*lgi"XI0''o 



F' 



363-31* O '" J »'*»" 



lojiogx/ot fl.»*83i«io-*» 



F' 



G' 



Figure 9. Three-section composite line with an intermediate 

 impedance load. 



and the new line-angle at B is 



h B = tanh" 1 (~^\ hyps (94) 



= tanh-f^» 



\ 1,000 J 



= 0.534 +j^ hyp. 



Having established the angle of the whole line at Ai, the architrave 

 impedance follows by formula (77) without further change. The 

 A -leak is also obtained by formulas (78) and (79). In order to obtain 

 the F-leak, and complete the n, the line is grounded at the other end 

 as at A 2 and the line-angles are developed towards F 2 . At C, we have 



