66 PROCEEDINGS OF THE AMERICAN ACADEMY. 



Equivalent n . Second Method. 



In the alternative method we have the regular formulas (83) and 

 (84), unchanged by the intermediate leak load. 



Equivalent T. First Method. 



To complete the equivalent T, free one end of the line, say F, as at 

 F 3 (Figure 12), and develop the line-angles towards A 8 . At the loaded 

 j unction DE we have 



G /D = y+ GfE mhos, (118) 



= 6.848,47 X 10~ 4 mho, 

 and, following (114) and (115), 



3 Z) = coth- 1 (J^f\ hyps, (119) 



77 



= 0.928,914 + j- hyp. 



The remaining line-angles follow regularly. The T-leak conductance 

 also follows from (86) without change, and the line-branch AO is com- 

 puted regularly by (18), (57), (59), and (87). 



To complete the T, free the other end of the line as at A 4 , and pro- 

 ceed, as above, to develop the line-angles towards F 4 . The T-admit- 

 tance must then conform to (88), and the line-branch impedance FO 

 to (89). 



Equivalent T. Second Method. 



The alternative method of arriving at the T-leak admittance is by 

 following (83) and (84). Freeing at A 4 (Figure 12), we have 



, ... sinh 8 D sinhS,. G fB , /1llM 



y J sinh b c sinndjB G fD 



and similarly, freeing at F 4 , we have 



. , sinhS c sinhS^ G fD , . . 



g = y 3 smh «. ■ ^ ■ ^ ■ ^r mhos. (121) 



Terminal Leak Loads. 



Equivalent (1. 



To arrive at the equivalent n of a composite line loaded with a termi- 

 nal leak, such as that represented at AF in Figure 13, first compute 



