Mathematical and Physical Papers. 227 



To use equation [11) we must compute fg and z (=v approxi- 

 mately) 



v = h-x-di=16-4. 833- 1.5=9. 667" 



f^=e-fe^=8. 06x74^x700=11,284. 



Substituting these values, and s = 0.5 in formula (11) we have 



„ 56.07X11284 -.oaqt— u A 



M=— — — — —— =130,o7o inch-pounds. 



9.667X0.5 ' ^ 



The correct solution is as follows : 



From (10) 0=^=.^ =0.25 and s=^ = 0.75. 

 Substituting these values in {14.) and (11), respectively, we get 



* /.,• ^f 150.52X700 orr ono 



from (i^j: M=— — — — —- = 87,203. 

 ^ ^^ 4.833 X. 25 ' 



T^ ,^ . 56.07X11284 or? o-n 



P'"" (">• 9.667X.75 ^^^•^^' 



which are the same, except for the slight difference due to decimals. 



