570 PROCEEDINGS OF THE AMERICAN ACADEMY. 



From this table we get, by reductions which need not be detailed : 



Temp. Interval. Total e. m. f. Mean e. m. f. per Degree. 



140° to 180° 9536 x 10~ 7 2384 x 10" 8 



140° " 218° 19320 " 2477 " 



100° " 218° 28140 " 2385 " 



From these reduced values we get: 



a = total e. m. f. from 100° to 140° = 8820 X 10" 7 

 /8 = " " " 140° " 180° = 9536 " 

 y = " « » 180° « 218° = 9784 " 

 Hencea + /? + y= 28140 " 



Taking now the results obtained after September, except those of 

 December 2, which are rejected because of strong evidence that uniform 

 temperature conditions were not maintained, we have 



Date Set of Temp. Max. Mean e. m. f. 



Couples. Interval. Min. (volt) per Degree. 



Oct. 28, 1905 (3) 100°.30 to 218°.60 A -^ C = 1.011 2375x10-* 



Dec. 16 

 " 20 

 " 22 

 " 23 



" 28 



180°.35 " 218°.53 " =1.015 2543 



179°.77 " 218°.63 " = 1.016 2545 



99°.93 " 140°.07 « = 1.021 2176 



99°.75 " 140°.02 " = 1.020 2178 



140°.25 " 180°.13 « = 1.017 2362 



From these values we get: 



Dec. 22 and 23 a = total e. m. f. from 100° to 140° = 8708 X 10" 7 

 "28 (3 = " " " 140° " 180° = 9444 " 



" 16and20 y = " " " 180° « 218° = 9660 " 



Hence a + (3 + y = 27812 " 



Oct. 28 a + £ + y = total e.m.f. from 100° to 218° = 28000 



Giving to the value of a + /3+yfound on October 28 one half as 

 much weight as to the value found by combining the December results, 

 and revising the December values of a, j3, and y accordingly, we get: 



Mean e. m. f. 

 per Degree. 



10 -'}8774X10-' 2194X10- 



" (after " ") = 8728 



/3 (before " ") = 9536 



u (after " ") = 9466 



rST " ?:2S - ^ - - 



1 9500 « 2375 



} 



