Constitution of the White Leghorn Breed. 



197 



Among the other half, lacking the inhibiting factor, a part should be 

 barred and the remainder black. 



If we assume that cf 325B, having the constitution C2B6/2I2, forms 

 gametes 



CBfi ■ Chfi 



and that the 9 9 [C^BhFJIi] form gametes 



CBfi • CBfl ' ChFi ■ CbFI 



the mating may be represented: 



c^ CBfi ' Chfi X 



9 CBfi ' CBfi • Chfi ' ChFI 



^d" 



99 



^2^2/2/^, white 

 C.Bhf'di, white 

 C2B2f'dij barred 

 C2Bhf2i2, barred 



' CiBhFjIi, white 

 C2h2FfIi, white 

 C2h2Ffi2, black 

 C2BhFfi2, barred 



The data presented above may be summarized as follows : 



In other words, among every 8 birds resulting from this cross, we 

 should expect to find 4 whites, one black and 3 barred. Of the 4 

 white, one should be homozygous and 2 heterozygous for barring; 



