152 



THEORY OF INJURY AND RECOVERY 



O could produce in 10.6 minutes if intact: but as O has diminished 

 to 0.917 times its original value it can produce in 10.6 minutes only 

 (1.45) (0.917) = 1.33. 



By adding this value to that obtained by formula (4) we find the 

 resistance after 10.6 minutes in sea water to be 87.44 + 1.33 = 88.77. 



In the same manner we may find the resistance at any given time 

 after replacement in sea water. A series of values so obtained is 

 given in Table II. It will be seen that they are in good agreement 

 with the experimental values. The calculated and observed values 

 are also plotted in Fig. 1, in which the abscisste represent the time in 

 the solution of NaCl plus the time of recovery in sea water (in the case 

 just discussed this would amount to 15.9 + 10.6 = 26.5 minutes). 



TABLE II. 

 Recovery in Sea Water after Exposure of 15.9 Minutes to 0.52 u NaCl. 



Proceeding in this manner with different times of exposure we obtain 

 the series of recovery curves shown in Fig. 1. The number attached 

 to each curve denotes the time of exposure to the solution of NaCl. 

 The observed results are plotted as dotted lines, the calculated values 

 as unbroken lines. 



It will be seen that the agreement is satisfactory throughout. In 

 general the greater the number of experiments which were averaged 

 to obtain the result the nearer it approached to the calculated curve. 



Let us now consider the behavior of tissues transferred from a solu- 

 tion of 0.278 M CaClo (which has the conductivity of sea water) to 

 sea water. In such a solution the resistance rises and then falls. If 



