qnae invenitiir —47'. 2", 3 n: 252^", 3 et angulus IILZ 

 — ?.o°. 4b'. 10". Ex triangulo igitur O^B oblinebitur 



Z -^^6= 1,2355284. 3oB=iz o". 51'. 4S''. 

 Z30=: 3, 2693495. 3^)0=1 S9- ^S. 12 



7r -5N ^ T> 7Z Z L n zz: 2c. 48. 10 



Zfin. 3oB r= 7, 9661789. ^ 



30B= o". 31'. 48". L-3 0= 68. 40. 2 



Ex O ia L 3 demirfo perpendiculo O O trianguluin 

 G^O dabit 



Z 3 0= 3. 2693495. ZlO = 3, 2693495 



Zfin. L JO = 9> 9691-50. Zcof. L 2 0= 9» 5608439 



Z 00 = 3, 2385245. ZCO = 2, 8301934 



ZLO zn 3, 3316297. 30= 676,3 



Ztang.OLOr=;9,9c6894S. ^0" T4.6 l 



OLO=3S°. 54'.i7". _ - ^ , . 



Ex triangulo L G O fit 



ZOo= 3> 23S5245. 

 l fin. O L O = 9* 7979784. 



Z L O = 3? 4405461. 



LO=: 2757,7 



ZLO-l-MO = 3, 7364-68:. 

 Z LO— Mo= I, 809^:597. 



5,5400279. Ztang. MLo= c, 65725 



ZLM= 2,7730139. MLO=:77°. 35'-^'^, 



Zred. — c, 3324317. 



l 1274, 8 = 3, 1054456. 



Z tang. 



