1S8 



EOGBRS AND McLEOD ON THR 



Jlxe 17, 1883. 



Fundamental Equations. 



Lamp ( 

 East. 1 



Lamp I 

 West. I 



+10 5 

 -i-7S.l 



- n.2 

 +70.3 



Without weights, 



= +0.042 +0.468(1 +1.07SC +SaT 



+0.040 -2.038/ +4.875C +8A7' 



- -0.067 +0.8:)S;( -1.02Sc +SaT 



-0.090 -2.138r( -4.188(; +SAT 



Normal Equations. 

 Assume : aT^o = +6:500 ; Co = +0-310 ; "o = -0 680. 



= 



Without wei;j;llt:f. 



+6^0.30 +12 3GS,( 



+0.081 - 4.278,1 



-0.075 - 3.4781 



= -0.0016 



L. K. ana I.. W, 



- 4.278'- 



+43.378C 



+ 0.74SC 



+0.08768A7' 



-3.478Ar 

 +0,7J8a7' 

 +4.00SAr 



8Ar = +6^018; Sc = -0.016; Sii = -0.004. 



With weights. L. E. only. 



= +Ô'.076 +2.128;i +0.328',- +1.80SAr 



+0.247 +0.328(1 +9.328C +5.95SAr 



+0.208 +1.808(1 +5.95SC +5,00SAr 



= -0.00002 +0.00148Ar 



8(1 = -a043. 



SaT = +0,014 ; 8t- 



-0.033 ; 



= -0.037 

 +0..538 

 -0.008 

 - 



s AT = +Ô.011; 



weights, L. E im.l L, W. 



+5.235.-( + 0.103c +3,678Ar 



+0.108(1 -HG.OKSr? +l,n78Ar 



+3 678(1 + 1.97SC +8.148Ar 



-0.0001 +0 00388 A 7' 



-0.034 ; 8.1 



0.000. 



With weights. L. W. only. 



= 



-0.113 +3.118(1 



1-0.291 -0.228(1 



-0.216 +1.878(1 



= +0.0050 



-0.22SC +1.878Ar 

 +7 3GSC -3.9b8Ar 

 -3.!l8Sr +3.148Ar 

 -O.0G05SAr 



8Ar = +0.083 ; Sr = +0.005 ; 8» = -0.013. 



Solution for 8(' 



0. 



Without weights. L. E anil L, W. 

 = -0.018 +0.872SA7' 

 SA 7' = +Ô.020; 8c = 0!000; Bti = 



-0.003. 



With weights, h. E au.l I., W. 



= +0.005 +1.517SAr 

 s. ,t. .''. 



8Ar = -0.003; Sc = 0.000; S(( = +0.009. 



With weights. L, E. ouly, 



= +0.0797 +1.9298 A 7' 

 .1. .V. ■•■■■ 



SaT = -0.041 ; 8c = O.OOO ; 8.i = -0.001. 



Wilh weights. L W. only. 



= -0.0793 +1.07788A7' 



.«. .x. -I- 



SaT - +0.071 ; Sc = 0.000; Ij = -0.007 



Jl-se 19, 1883. 



