[mcnaughton] electric SERIES TRANSFORMERS 



191 



The interpretations of this equation for ij a Single and Double 

 Exponential, Oscillatory, Harmonic and Constant are considered. 



Case 1. Single Exponential Transient of Current. 

 Let 



(4) 



(5) 



Then 



-at 

 i, = A (1 - e ) 



— at 



di = + A a e 



dt 



and substituting in Equation (3) and writing the 

 particular solution 



— at 

 - M Ni A a e 



L. N, 



(6) 



— a + 1^2 

 and hence the complete solution is 



— at 



(7) 



i, = K e 



Let i, 



Then 



K = 



which substituted in Equation (7) gives 

 (8) M Ni A a 



L, N, 



- a +R2 



l7 



- R,t -at 

 e L, — € 



