41 
2310 : 449 = 0,48573 : 0,09441, unde prodit valor 
proxinmus t — 1,46203. 
Instituamus denuo talem operationem, ét cum sit 
t=1,46208, erit ;=0,68306, hincque t+==2,14604, unde 
colligitur membrum IV = 1,03586, ideoque HI+IV=2,5803. 
Tum vero cum sit f+:— 1,52306 et g-+t — 1,82605, 
erit membrum logis et 1 =1,35130, ecrumque 
summa — 2,58542, ideoque error E = 0,00161. 
Quoniam igitur valor t—1,55644 dederat errorem 
+ 449, et valor t — 1,46203 dederat — 162, fiet hinc 
vero proximus valor t— 1,48101; unde fit : — 0,67249 
et angulus D — 562.5’. Porro membrum IV — 1,03911, 
… ideoque II+IV=2,59028. Deinde cum sit f+==1,51159, 
erit membr. [= 1,22044; tum ob g+t— 1,85098 erit 
membrum [= 1,36051, ergo I + II — 2,58995, à quo 
summa [I IV -sublata relinquit errorem — 0,00033, 
quem pro mihilo reputari liceat. 
En ergo nacti sumus hanc solutioném: Quoniam 
tertium membrum refert totam basin AB >; primum vera 
intervallum AX et secundum intervallum BY, si poria- 
mus À B— III membro — 1,55117, erit AX — 122044, 
BY — 1,36051, ideoque intervalla A Y — 0,19066 et 
…BX—0,32173, ac angulus D — AXO — 56. 5’. 
