36 
Then, Log. Rad.—Tan of Lat. 51° 11’ 0” = 0:0944741 
Log. Tan. Declination, &c. 23° 58’ 31” = 9°6470786 
Log. Sine, Ascensional Difference 33° 28’ 14” = 9°7415527 
And oan 28’ V4 2213" 53" Substract and add 6". 
3 46™ 75 = Hour of Sunrise at Midsummer A.D. 1897. 
2 
7 32" 145 = Length of night at Midsummer, also 
length of day at Midwinter, 4.p. 1897. 
6» 
Gis 13h aay 
8" 13™ 53° = Hour of Sunset at Midsummer, A.D. 1897. 
16" 27™ 465 = Length of day at Midsummer, also 
length of night at. Midwinter, A.D. 1897. 
aaa Log. Rad.—Tan. Lat. 51° 11’ 0” = 0:0944741 
Log. Tan. Declination, &c. 24° 20’ 44” = 9°6555944 
Log. Sine Ascensional Difference 34° 13’ 6” = 9°7500685 
But 34° 13’ 26” = 2" 16™ 53*8 ; Substract and 6°. 
GeO 
2 16 53:8 
3" 43™ 6° = Hour of Sunrise at Midsummer, B.c. 890. 
9 
a 
7» 26™ 12° = Length of night at Midsummer, also 
length of day at Midwinter, B.c. 890. 
BEY HOES Oe 
216 54 
8» 16™ 545 — Hour of Sunset at Midsummer, B.c. 890. 
a 
16" 33" 48° = Length of day at Midsummer, also 
length of night at Midwinter, B.c. 890. 
Length of day B.c. 890 = 16" 33™ 48° 
The same A.D.1897 = 16 27 46 
The difference = 0" 6™ 2° 
This difference would be the same had we used the longer 
method. But in that case the length of day would for each 
of the years appear to be about 1” 20° longer. 
