128 ESSAYS AND OBSERVATIONS 



Let SM, perpendicular to CG, meet CG 

 }h M : It is evident, becaufe the fedor ACG 

 is common to both the fedors ASG, ACB^ 

 that, it" the fedor ASG be equal to the fedor 

 ACB, the triangle SCG will be equal to the 

 fedor BCG j and therefore the line SM will 

 be equal to the arc BG ; if the fedor ASG 

 be greater than the fedor ACB, the triangle 

 SCG will be greater than the fedor BCG j 

 ^nd therefore the line SM will be greater 

 than the arc BG : and, if the fedor ASG be 

 lefs than the fedor ACB, the triangle SCG 

 will be lefs than the fedor BCG ; and there- 

 fore the Kne SM will be lefs than the arc 

 BG: that is, if the arc AG be greater, 

 equal, or lefs, than the true anomaly of the 

 excentric, the line SM will be greater, equal, 

 or lefs, than the arc BG ; and therefore, the 

 lefs the difference is between the line SM 

 and the arc BG, the lefs will the difference 

 be between the arc AG and the anomaly of 

 the excentric. 



Because the triangles GCH, CSM, are 

 fimilar, CG is to GH as CS to SM ; that is, 

 the radius is to the fme of 50" 51'. 093893 



as 20589 to CM, 



The 



