224 A NEW and UNIFERSJL SOLUTION 



I. To compute />, the fir ft term in the feries, approximating 

 to BC : Since f zz e =: i, we have 

 ^ tan A =: fee. 45^ zz 10.1505150, 



therefore A = 54° 44'. 



Then fin x = tan - X fin 45" j and / =: 90° — 2?.. 



Now log. tan — = 9.714005 1 

 log. fin 45° — 9.8494850 



log. fin X = 9.5634901 = fin 21 ° 28'. 

 Therefore X = 2 1 ° 28", and/" = 90° — - 2X = 47° 4' ; this value of 

 p is lefs than BC. 



fin f- 



2. To compute the fecond term p', we have e zz t x — 



^ fin 21° 28' J » ^ A — . s^ r ^ /-♦ — fii^ 2 1 '28' - g 



— ;^ — s, and tan A = <? X fee 45* = — — r v fee 4C . 



arc2i°28 arc 2 1 ''28 ^ ^'='- '*•> 



log. fee 45° = 10.1505150, 



log. fin 21° 28'= 9-5634335 



fum — 10= 9.7139485 

 add conftant log. — 3.5362739 



13.2502224 

 fubtrafl log. 1288' {— 21* 28*) z= 3.1099159 



log. tan A = to. 1403065 

 therefore A =: 54* 5' 54". 



Then, 



