w 



Of KEPLER'S PROBLEM. 227 



log. cof(p= 9.480538 j; 

 log.cof^-— — = 9-9974523 



2 



19.4779908 

 log.cof^^t^r: 9.6058923 



log. cof -(I/ = 9.8720985 

 therefore ^ = ^1° 51', 

 confequently p = <p — 'i' = 30° 33', which is lefs than BH. 



fin £ 



2. For the next term />', we have e ■=. tX ^ 



2 ^ 



fin 14° All -jo" , , , /I ^^ fin m 



„ T o > -/ ; and «3 + (-, — \) x - — — •. 



arci4 43 30 ' 'V e^ 



log. fin 14° 43' 30" - 9.4051412 



add conft. log. = 3-5362739 



fum — 10 = 2.9414151 

 fubtraiSl log. 883'.5 = 2.9462066 



log. <? = 7.9952085 

 log. - = 0.0047915 



log. - zz 0.0095830, and -j = 1.022410, 



C 6 



alfo - — I = .022410 = a. Now, log. fin m — 9-9375306, 



therefore log. — »- = 9-9471 1361 and — ~ — .885347 = b. 



The 



