200 



To find a divisor of two dimensions 



34 9 X 3— 34=r -7 



19 9 6 g 4x3—19= -7 



10 2 6 D=— =3 1x3— 10= -7 



7 _„ 6 '- 0x3— 7= -7^ —7— 1x0= -7 ?=7 



10 1 x3— 10= -7 



Tlie divisor is «■ + j or 3* + 7 = 0. 

 To find a divisor of three dimensions : 



27x18 — 442 = 44 44— 9xlS = -91 



8x18—133 = 11 3 30 11— 4xl5 = -49 



1 X 18— 10= 8 30 8—1 X 15= -7 



Ox 18+ 35 = 35 _^i! 30 35—0x15= 35 ^Ig 



-1x18 + 113 = 92 92-7x15=77 



/.==^ = -15 q=42,r=-35 

 The divisor is x——x + -x~-rT or 18« — I5x + 4:2x —35=0 



lo lo 10 



To find a divisor of four dimensions, according to the ge- 

 neral statement of Gravesand's method, or the abridged mode 

 ■which was given above : 



1.2.3.4 



4 2 



The divisor is x — 3« + i=0 



From 



I 



