448 Professor Kane on the Action of Ammonia, &c. 
Giving a mean result of 
Mercury 83,68 | 
Oxygen 6,60 
Ammonia 4,10 roe 
Water 5,62 
on abstracting the water, we have— 
Mercury 88,67 
Oxygen 6,99 + 100,00 
Ammonia 4,34 
The only analysis of this substance that I am aware of having been published, is that 
of Guibourt, already quoted, and he considers it to be a compound of oxide of mer- 
cury and ammonia in such proportion that the hydrogen of the ammonia could con- 
vert the oxygen of the oxide of mercury into water, consequently his formula is the 
following (3 Hg + 2NH®) and the per centage result : 
Mercury 88,08 
Oxygen 6,95 $ 100,00 
Ammonia 4,97 
with which my analyses may be considered as completely agreeing. In the abstracts 
of Guibourt’s paper that I have seen, there is not any notice taken of the water 
present ; but yet its constant value shows it to be a chemical ingredient, and we have 
its atomic proportion, thus— 
2Hg _ 405,6 _ 83,68 jy 83:68 
SH wee Nin Soteati. 5: 
The compound (3 He +2NH +4H) gives us in per cent. composition, the following : 
Mercury 83,72) 
Oxygen 6,60 | 
Ammonia 4,72 pe 
Water 4,96 J 
a result agreeing very closely with that of experiment. 
Admitting that the azotic element is engaged in the combination as amidogene, 
and not as ammonia, the above formula converts itself into 
(2 Hg +(2 NH?+ Hg) +6H) 
a method of arrangement which we have already met with as an element of the yellow 
powder, formed by water on white precipitate. 
