ORIGINAL COMMUNICATIONS. 
Investication of a Stmete Rute for Finpine the Numer of 
Entrre Hexaconat Facets contained in a Given Crrcre. 
By H. M. 
I. Tue area of a hexagonal facet (the diameter bisecting 
3 
the sides bemg = 6) = ss 6? = & X *866025. 
II. The area of a circle whose diameter = N6d is N26? 
x 7854. 
Ilt. Then the number of areas in the circle, each equal 
N28? x -7854 eee 
to that of a facet, 1s  §2 x 866025 == IN? x 90691 = N?2 x 9 
oe 2 : 
or 7 oN nearly 
——— 
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2 EX 
= \ 
VOL, VI. H 
