1216 
of Pe © + Az, 1. + Ag, 2) a Az, 
EE) B U, Eik As, Yet Ay, Za i Az, 
and the composition of the equilibrium £" is: 
of Be ome Le, Ha = Ay, aia Lz, 
khen jj 4 n 
+) vi 2 Co Az, Ya = Ay, it Az, 
Herein Aw, Ae,... are ‘defined by (9) and (10); it is apparent 
that they may be as well positive as negative, 
In order to be able to convert the equilibrium Zr into LZ’, it 
must be possible to satisfy 
ah, bal A Sh ae eo) See 
in which all coefficients must be positive. 
It follows from (21): 
a, 4a, by b+. 
at, ae, >... = 5, (a, + Ar) + be, + Aa) ..: 
ay, + Ay +--- =), (y, + Ay,) Hb, (U, + Ay.) +. 
ete. When we put a, — 4b, =c,; a, — 6, = c,; ete. then the previous 
equations pass into: 
Eet Oja Tr On 0 
EEH te, + mar bar nn | (22) 
CY, + ey, +-..=—=b Ay, + b,Äy, +.. 
ete. We ean eliminate c‚...c from the n equations (22). We add 
them viz. after having multiplied the 1st by u,, the 2" by u,, ete. 
As w, y,... viz. satisfy (9), they also satisfy: 
u, Hut, + HY +. = 9 | (23) 
u, + ut, + uy +-.- == 0 
etc. (22) passes then into: 
0=b, [ujAc, + u, Ay, +... Hb, [u,Ae, Huy, +] | (24) 
++. dy [p Aan + Weyn +] aay 
Also-it appears from (9) that we may satisfy (23) by taking 
pb, = ads) =a de), =.5 ie = Cd, dk =... ete ner 
fore (24) passes into: 
0 = Bb, [d(z), Az, + diy), Ay, +...]+ 5, [d(z), Az, + dy) Ay, +...] + oe 
for which we may also write: 
O= 6,02, AZ Foc tn Bae Oe EN 
Is must be possible to satisfy (25) by giving positive values to 
b, b,... When we consider only equilibria in stable (or metastable) 
condition, then d?Z,, d?Z,,... are positive; it is, therefore, not 
possible to satisfy (25) and consequently also not (21). 
