et 
( 329 ) 
if there be a point in the perpendicular ?,-drawn on the basis 
QS, the length and breadth are equal to each other. Mutatis mutan- 
dis the same also concerns the perpendiculars, drawn from Qand S 
on the opposite sides. 
if there were a point in the intersection of the three perpendicu- 
lars, all three of the measurements would be mutually equal. Fora 
skull this would signify a mathematical roundhead, but this does 
not occur in reality. 
if we draw lines, that we will call radii, from Z to the basis, we 
shall see in each radius the points, of which the proportion of the 
Breadth and Length is constant ; 
eg. by Rp is By i= 9211 
mog Pe Dn 2: | Dy 
Skulls, that, seen from above, are conformable, lie in the same 
radius of R; 
a radius, drawn from S to QR, combines the points, of which 
the proportion of the height to the length is constant; 
es goby Sean bee, = eT b 
» Srem Bet 2:3 
Skulls, that, seen from the side, are comformable, lie in the same 
radius of S; 
by a radius, drawn from Q to &S, the proportion of the height 
to the breadth is constant ; 
6. iby Gl ie ie — 9: 11 
KUUR Eee = Ds Sy, 
Skulls, that, seen from the back, are conformable, lie in the same 
radius of Q. 
To draw a graphic point in the diagram, is very simple. For a 
skull rel. Z = 120; rel. B= 90 and rel. H=90, we find the point 
by taking the intersection of the lines 120 Z and 90 B, which is 
then naturally the intersection for 90 H. 
If we draw in the figure the five skulls, which ToprnarD de- 
scribes as differing most in form: 
