( 785.) 
being different for the molecules of different kinds, the denominators 
v— should strictly speaking also have different values. As it is here, 
however, orly our purpose to examine what function « is of .V, we 
may disregard these differences. 
So if we take into consideration that ‘/,m,N’«? = MRT, the 
number of particles which passes from the liquid to a space where 
the potential energy is maximum and the kinetie pressure = 0, 
amounts to: 
di (1 —®) a, +a, | LORT | b, (L— 2) a 
ale v | sb 
en er Ie es) 7 
var 
or 
5 \ (l-w)a, Ha, } 49RT ble) a be 4 RTI la 
} v | u—b Vv 
N= CY Te RT 
RN' 
where (= bas —. 
2am 
5. It remains to show that the expression in the exponent agrees 
with u — f(7') of equation (8). 
Now, if we leave the pure functions of the temperature out of 
consideration, the thermodynamic potential becomes : 
5 db da 
RI 
de | da: dia: 
pv — RT l(vw—b) — = — # | ——— — —; + ATI (1—2). . (10) 
UA didi v 
if / may be considered as a constant. This is, of course not the case 
in the liquid state, and accordingly we can only expect to obtain 
agreement between (9) and (10), when we neglect terms with higher 
b 
powers of — 
:: 
r a f 
If we write pv = RT — — — , the terms with a from equa- 
vv —O v 
tion (10) become: 
and so these terms perfectly agree with those of (9). 
hb 
With negleet of the higher powers of —, the terms with 4 from 
5 
51* 
