© (922 ) 
by substituting in (9) the values of ft, A,, 4, ete. obtained from 
the consecutive numbers in the vertical ranges of (8). 
In order to determine the integral (4) the number of layers im 
has to be supposed =o; so it is evident, that in the functions P, 
Q and R, i.e. in the expression (9), we only need to retain the 
term with the highest exponent. 
This term is: 
mrt! 
18 ml 
We therefore only have to find the order number of each of the series 
in the vertical ranges of (8), and the value of the constant difference. 
For the term with da? for instance this determination gives: 
OA 
2 
2 8 Wed ii 
10 6 
12 14 
24 6 rel 6m? ee m' 
36 20 123.4; > 4 
44 
80 
m? 2m? 
In the same way we find: P=—; Q= ca 
The series in the first term of (7) now becomes, if we omit the 
index of «, 
Me Ao. eam hee 
— gg" — —— ada +- — da” 
») 3 A 
Now observing that mda == R,— R; = t, and reducing the fractions 
we obtain: 
| dl bd A . 9 
19 [ Gm? a? — 8m?at + Smit] 
bringing ma? outside the brackets, 
mae 6 8 t ae a 
12 a ie 
Ak, 2 
Putting —==o we finally have: 
oD a s Py, 
or 
> 
ma? 5 
ni [6-80 HF 30]: ve Ar ore He oP 
Operating in the same way with the two other series in (7) we 
find for the coefficients of the terms with da and da’ successively : 
