( 11709 
Gd, 
Further we have the following saturation lines: 
en the saturation line of CuSO, .5 H,O + CuCl, . 2H,0 
Te a » » CuCl, . 2 H,0 + Na,Ca (SO), . 2 HO 
me : » 9 NaCl + Na,Cu (SO), . 2 H,O 
MG Los a. » » OuCl, .2H,0 + NaCl 
er pe » » NaCl + Na,SO, 
las 24 » 9» Na,SO, + Na,Cu (SO,), . 2 H,O 
GP! ve vs » » Na, SO, + Na,SO,.10H,O 
Ga ss Ee » >» Na,sO,.10H,O + Na,Cu (SO), 2 H,O 
ER 5 » » CuSO,.5 H,O + Na,Cu (SO,),.2H,0 
Instead of three saturation points as at 35°, four are found here 
namely : 
n saturated with CuCl, .2H,O + CuSO,.5H,0 + Na,Cu(SO,), .2 H,O 
m 5 „ CuCl,.2H,0 + NaCl + Na,Cu (SO,),. 2 H,O 
/ ‘5 5, NaCl + Na,S0, + NaCu (SO,), . 2 HO 
1 ss » Na,SO, + Na,SO, .10H,O + Na,Cu (SO), . 2 H,O 
As may be readily deduced from fig. 2, at 25°, in presence of 
solution there can exist: 
CuSO,.5 H,O by the side of CuCl, .2H,O or Na,Cu (SO,), .2H O 
but not to NaCl, Na,SO, or Na,SO, . 10 H,O. 
CuCl, .2H,O by the side of CuSO,.5 H,O, NaCl or Na,Cu (SO,),.2 H,O 
but not to Na,SO, or Na,SO, .10 H,0. 
