(12935) 
stance intersects the locus. And if we knew this locus perfectly, and 
b ; 
also the value of — for that definite substance, we could determine 
a 
Dn 
the critical point by determining where — intersects the given locus. 
g 
b nes 
For greater values of 7 the curve a for the definite substance lies 
g 
below the locus, and for smaller value of r above it. And it 
db}. 
db 
follows already from this that (5) must be smaller than neon 
VS kr QU}; 
ke 
Then it follows by comparison of (V) with (VI) that SL must 
ar 
be positive. This means that sr is equal to 8 only for r# == 8, or for 
constant value of 64; but in all other cases, so if 6 decreases with 
v, it is smaller than 8, and the more so as the variability of 6 
is stronger. 
. . a rr 
Now the value of the factor of — for RZ), does not only depend 
g 
rs 
C 
= =e OLS ==: 
(7 5 1) ns C, 
on sr. This factor is Representing this factor by F, 
dF de, de, C, ; . ; de, de, 
NINE Sa . And —- being constant, 2 ——=——. 
For dr. edr c, cdr ‘e.dr 
dk de, 
Hence en . To find this result, we might also have written 
Far cdr 
f a (ek el 64 1 AE 
the factor of r ——. So if for all substances for 
: 0 
by (f—1)r rs 27 rs 
8 c 
which 6 is variable with v rs < 8, then RT, > — 
27 by and this result 
might also have been arrived at in a simpler way. 
Let us imagine for this purpose two substances with given a and 
b, — the former with constant 6, the latter with 5 decreasing with 
diminishing v. If for given value of 7 we plot an isotherm for both 
substances — we see at once that the isotherm for the second 
substance will always lie below that of the first substance. As for 
every value of v the quantity v—d is greater for the second substance 
7 
than for the first, is smaller for the first substance than for the 
U 
a . . hl 
second, and — being the same for the two substances, p, << p,. For 
p 
