15 
In the special example of Hg Wa,—=2 x 11,0 x 10-2 (as mercury 
is bimolecular for 7%), so that we have from 
(RT;)? ‘64 
ge dU 
Pk 27 
with R=1 : 278,1 and 4— 27/28: 
fh RE 0 16 
= (278,1 x 2 X 11,0 10-2)? = — X (60 08)? = 8252. 
Pk ( 7 
Now 7, =«: f, log pr = y—f, hence 
Jeter 8252, or «7 == 8252/7. 109, 
TO lt 3 el —— e : e ‘ ° 
or also 
2 log « = log 8252 — 2 log f +4 —f, 
yielding 
| f 2 log f =o — A log. @ 160, He er 5) 
from which / (in the case of mercury) can be calculated. 
If for the calculation we choose the four temperatures beginning 
with the boiling point, because f changes only little there, we find 
— seeing that 
yo Der ieee Os 
| Tan 1 
follows from (4) by subtraction — successively between 
log 1495,6-log 760 
(1: 629,8)-(1 : 673 1) 
log 2996,1-log 1495,6 Ee 
== —— = 2937|y = 7,539-2,881 — 4,658 
(1 :673,1)-(1 :723,1) 
__log5435,0-log2996,1 
—(1:723,1)-(1: 773,1) 
The value of y must, namely, everywhere be diminished by 
log 760 = 2,881, because in log p the pressure p must not be expres- 
sed in m.m., but in atm., because also aj is expressed in atm. 
According to (5) the following equations follow from the found 
values of # and 4: 
f— 2log f = 4,570 —6,918 + 3,917 = 1,569 | 
= 4,658—6,936 + 3,917 = 1,639 |. 
= 4,595— 6,922 + 3,917 = 1,590 | f= 2,322 
From «= fT), and y= f+ log pe we find then at once: 
Tg=1258 ; 1224 3; 1245 
Pill ; BKB ; 187,7 
giving on an average 7, = 1242° abs.; p, = 187 atm. 
356,7° and 400°. x= 
—2878 y — 7,451-2,881 = 4,570 
4009 ;, 450° & 
450° ,, 500° « 
—2892)y — 7,476-2,881 = 4,595 
9 
